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2014-10-26T15:40:15+02:00
A=(7^15·7^32:7^36)^10:7^24]^7:7^(19·31)=
a={[7^(15+32-36)]^10:7^24}^7:7^589=
  =[(7^11)^10:7^24]^7:7^589=
  =[7^110:7^24]^7:7^589=
  =[7^(110-24)]^7:7^589=(7^86)^7:7^589=7^602:7^589=7^(602-589)=7^13
b=[(5/3)^22:(5/3)^18:((5/3)²)²}^205·(5/3)^4·(3/5)^4=
  =[(5/3)^(22-18-4)]^205·(5/3)^4·(5/3)^(-4)=
  =[(5/3)^0]^205·(5/3)^(4-4)=1^205·(5/3)^0=1·1=1
a)   7^13·1=7^13
b)  7^13>1
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