Răspunsuri

2014-10-27T01:37:35+02:00
CH4 + 2O2 -> CO2 + 2H2O
CH3-CH3 + 7/2 O2 -> 2CO2 + 3H2O

224 L = 10 moli, deci numărul molilor de etan + metan = 10

 \frac{10}{3+1} = 2.5

2.5*1= 2.5 moli metan
2.5*3= 7.5 moli etan

1 mol metan foloseşte .................... 2 moli O2
2.5 moli metan ...............................x= 5 moli O2

1 mol etan ................................. 7/2 moli O2
7.5 moli ..................................... x= 26.25 moli O2

26.25+5=31.25 moli O2 consumaţi

31.25*22.4 = 700 litri O2

700 * \frac{100}{20} = 3500 \ L \ aer









2 5 2