Răspunsuri

2014-10-24T16:28:39+03:00


(a+b+c)/3=31; (a+b)/2=21, deci a+b=2*21=42; (b+c)/2=40, deci b+c=2*40=80. de aici c=80-b si mergem si inlocuim in prima ecuatie, adica avem a+b+80-b=3*31=93, de unde a=93-80=13

b=42-13=29 si c=80-29=51