A) [(2la puterea a 5)totu la a 6 + 25 la puterea a 4 - 13 la putera a 2] : [8 la puterea a 10 + 625 la puterea a 2 - 169]


b) 3 la puterea 105 : ( 5 la puterea 221 : 5 la puterea 220 - 2)totu la 45 : 27 la puterea 20



c)4 la puterea a 3 : 2 la puterea a 2 - 18 la puterea 0 x [5 la puterea a 10 : 5 la puterea a 9 - 6 la puterea a 2 x ( 7 la puterea a 15 : 7 la puterea a 13 - 7 la puterea a 2)]


d) 25 la puterea 0 + 37 :[ 2 x 3 la puterea a patra - 5 x (2 la puterea a 7 : 2 la puterea a 4 - 3 la puterea a 2 : 3) totu la a 2]


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Răspunsuri

Cel mai inteligent răspuns!
2014-10-23T22:45:00+03:00
A)^-putere
=[(2^5)^6+(5²)^4-13²]:[(2³)^10+(5^4)²-13²=
=[2^30+5^8-13²] /[2^30+5^8-13²]=1
b)=3^105:(5^(221-220)-2):(3³)^20=
=3^105:(5-2):3^60
=3^105·3:3^60=3^(105+1-60)=3^44
c)=(2²)³:2²-1·[5^(10-9)-6²·(7^(15-13)-7²]=
=2^6:2²-1·[5-6²·(7²-7²)]=
=2^(6-2)-1·(5-6²·0)=
=2^4-5=16-5=11
d)=1+37:{2·81-5·[2^(7-4)-3^(2-1)]²=
=1+37:{162-5·[2³-3]²}=
=1+37:[162-5(8-3)²]=
=1+37:(162-25)=
=1+37:137
probabil ca ai gresit cand ai scris ex.in loc de 37 trebuia 137

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