1descompuneti in factori primi numerele.52,36,160,3000 2aflati c.m.m.d.c al mumerelor.12,22 25,15 56,40 810,720 423,228 3care dintre perechile de numere sunt prime intre ele.42,27 50,63 22,45 35,49 4sa se arate ca sunt prime intre ele.a=2n+11,b=n+5 a=2n+3,b=5n+7 5determinati numerele. (a,b)=12 si a+b=96 (a,b)=15 si ab=6300

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Răspunsuri

2014-10-23T22:19:54+03:00
1)52=2²·13
36=2²·3²
160=5·2^5
3000=3·2³·5³
2)
12=3·2²
22=11·2
(12,22)=2
25=5²
15=3·5
(25,15)=5
56=7·2³
40=2³·5
(56,40)=2³=8
810=3^4·2·5
720=3²·2^4··5
(810,720)=3²·2·5=90
23=1·23
228=19·2²·3
(23,228)=1