Răspunsuri

2014-10-22T20:34:14+03:00
Este o formula 
x^0+x^1+....+x^n=x^(n+1)/n-1

1+6+6^2+....+6^2013=6^2014/5
2014-10-22T20:57:38+03:00
Formula dupa care rezolvi este : 1+x+x^2+x^3+...+x^n=[x^(n+1) -1]/ (x-1)
In cazul tau: 1+6+6^2+...+6^2013=( 6^2014 -1 )/ 5
3 3 3