Răspunsuri

Cel mai inteligent răspuns!
2014-02-27T12:16:55+02:00
f:R\Rightarrow R,f(x)=\frac{3x}{2}-27=\frac{3x-54}{2}
f(10)f(11)...f(20)=\frac{3*10-54}{2}*\frac{3*11-54}{2}*...*\frac{3*20-54}{2}=
=\frac{-24*(-21)*...*(3*18-54)*...*(6)}{2^{11}}=0
3*18=54
Deci produsul este 0.
Sau solutia mai usoara
f(x)=\frac{3x}{2}-27=\frac{3x-54}{2}
f(18)=0
Deci f(10)f(11)...f(20)=0


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