aratati ca numarul
n=3⁹*32¹¹/2-16⁶*2*6²⁷ , n=3²³*4²³-2²¹*6²³ demonstrati ca numarul ''n'' este patrat perfect

1
semnul* este inmultire si/ impartire
va rog frumos cine poate sa ma ajute

Răspunsuri

2014-10-26T02:38:13+03:00
n=3⁹*32¹¹/2-16⁶*2*6²⁷=3⁹*(2⁵)¹¹:2¹-(2⁴)⁶*2¹*2²⁷*3²⁷=3⁹*2⁵⁵:2-2²⁴*2*2²⁷*3²⁷=3⁹*2⁵⁴-2⁵²*3²⁷=3⁹*2⁵²(2²-3¹⁸)
3⁹=3³ la²
2⁵²=(2²⁶)² e patrat(2²-3¹⁸)

n=3²³*4²³-2²¹*6²³ =3²³*(2²)²³-2²¹*2²³*3²³=3²³*2⁴⁶-2⁴⁴*3²³=2⁴⁴*3²³(2²-1)=2⁴⁴*3²³⁺¹=2⁴⁴*3²⁴=(2²²)²*(3¹²)² patrat perfect