Răspunsuri

2014-10-22T09:07:06+03:00
1/(1+√2) = (1-√2)/(-1)
1/(√2 +√3) =(√2-√3)/(-1)
1/(√3+√4)=(√3-√4)/(-1)
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1/[√(n-1) +√n] = [√(n-1)-√n ] /(-1)
S = (-1)[1-√2+√2-√3+√3-√4+..........+√(n-1) - √n = (-1)(1 -√n) = √n - 1
√n - 1 = 2014 ⇒ √n = 2013 ⇒ n=2013²