Răspunsuri

2014-10-22T08:08:21+03:00
X+y+y+z=123+257
x+y+z=380
x+y incape in 5x+7y de 5 ori ca se epuizeaza x
7y-5y=2y
y+y incape in 2y+2z de doua ori
5x+7y+2z=123.5+257.2
5x+7y+2z=615+514
5x+7y+2z=1129
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