Răspunsuri

2014-10-21T22:11:47+03:00
S= 2^{0} + 2^{1} +2^{2}+...+2^{2003}=2^{2004}-1
 (formula de calcul...daca vrei iti dau si demonstratia)
Ultima cifra al lui [tex]2^{n}=2 daca n=M4+1, 4 daca n=M4+2, 8 daca n=M4+3 si 6 daca n=M4.
2004=4*501=U(S)=6-1=5