Răspunsuri

2014-10-21T00:19:48+03:00
1,(6)=(16-1)/9=15/9=simplif.cu 3=5/3
0,5=5/10 simplif.cu 5=1/2
1intreg1/4=(1·4+1)/4=5/4
0,(6)=6/9=simplif.cu 3=2/3
2intreg1/4=(2·4+1)/4=9/4
-5/3-[(1/2-5/4)(2/3-9/4)]=
=-5/3-[(2-5)/4·(8-27)/12]=
=-5/3-[(-3/4)·(-19/12)]=simplif
=-5/3-19/16=aducem la acelasi numitor
=(-5·16-19·3)/48=
=(-80-57)/48=-137/48