Răspunsuri

2014-02-25T19:54:31+02:00
A=1989^{2} -1989-1988=1989(1989-1)-1988=1989*1988-1988=1988(1989-1)=1988*1988 \frac{x}{1988} /4= \frac{497}{1988*1988} ---->
x =  \frac{1988/4*497}{ 1988^{2} } = \frac{ 497^{2}  }{ 1988^{2}  } =( \frac{497}{1988} )la puterea2=  \frac{1}{4}  ^{2} = \frac{1}{16}
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