Răspunsuri

2014-10-19T22:58:03+03:00

[(1+1/2) + (1+1/3) + (1+1/4) +..............+ (1+1/1007)] /{2012-[ (1-1/2)+(1-1/3)+(1-1/4)+...........+(1-1/1007)]}  =

[1·1006+(1/2+1/3+1/4..1/1007)]/{2012-1·1006-(1/2+1/3...+1/1007)} =[1006+(1/2+1/3+.....+1/1007)]/[1006+(1/2+1/3+......+1/1007] = 1