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2014-10-18T19:48:59+03:00
Folosesti formula  a^{log _{a} x} =x.

3^{log_{3} 9 - log _{3} 10  }  4^{log_{4}4-log_{4}5  }  6^{log _{6}9-log_{6}6  } =
3 ^{log_{3} \frac{9}{10}  } -4^{log_{4} \frac{4}{5}  } - 6^{log_{6} \frac{9}{6}  }  =
 \frac{9}{10} -  \frac{4}{5} +  \frac{9}{6} =
 \frac{48}{30} = \frac{24}{15}= \frac{8}{5}