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2014-10-18T15:26:26+03:00
Fie ABCD romb
P=AB+BC+CD+DA=20
AB=BC=CD=DA=5 cm
DB=6 cm diagonala DO=OB=3
in triunghiul AOD dreptunghic aplicam teorema PITAGORA AO^2=AD^2-OD^2
AO^2=25-9
AO^2=16
AO=4 cm
AC=8 cm diagonala AO=OC=4 CM
A=(diagonala1xdiagonala2):2=(DBXAC):2=(6X8):2=24 cm