Răspunsuri

2014-10-18T12:27:12+03:00
4.8 cm. tiung drept in A; DEM:se aplica teorema catetei  1) AC:2=BC*CD; 2)  AB.2=BC*BD
si teorema inaltimiiAD.2=BD*DC :AB=8;AC=6 rezulta aplicant pitagoraAC2=AB2+AC2:AC2=64+36;BC=10
1)36=10*CD ;CD=36/10  2)64=10*BD; BD=64/10
AD.2=64*36/100;  AD=48/10; AD=4.8
2014-10-18T14:02:47+03:00

ip² = 64+36 = 100 ⇒ip=10   fie m si n lungimile celor doua segmente determinate de intersectia inaltimii cu ipotenuza;  ... aplicand teorema catetei⇒ 8²=10·m ⇒m=6,4  ⇒h²=8² -6,4² =23,04 ⇒h= 4,8