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2014-10-16T01:38:59+03:00
A)⇒2^6·3^10:2^4·3^6:3²=6^x
⇒2^(6-4)·3^(10-6):3²=6^x
⇒2²·3^4:3²=6^x
⇒2²·3^(4-2)=6^x
⇒2²·3²=6^x
⇒(2·3)²=(2·3)^x
Notam (2·3)=t
t²=t^x
⇒x=2
b)
⇒(2²·2³)^15:(2²)^5:2^6=2^x
⇒(2^5)^15:2^10:2^6=2^x
⇒2^75:2^10:2^6=2^x
⇒2^65:2^6=2^x
⇒2^59=2^x
⇒x=59

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