Calculati , tinund cont de ordinea operatiilor :

a)10-9÷[16-(2·3+3² - 2³)] ;
b)(5-5÷5+5⁵÷5⁵ - 5)·5⁵ ;
c)9+2²·(3²÷9-1)÷2³+100⁰ ;
d)10+3³·2⁻5·(2⁴÷8-2)²+5·2² ;
e)3²+[2³÷2-2¹⁷÷(2²)⁸]÷2 ;
f)(3³)⁴÷9⁵-(4³·2⁵)÷2¹⁰ ;

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Răspunsuri

2014-10-14T15:37:56+03:00
A) 10-9÷[16-(2×3+9-8)]=10-9÷[16-(6+1)]=10-9÷(16-7)=10-9÷9=10-1=9; b)(5-5÷5+5÷5-5)×5=(5-1+1-5)×5=0×5=0; c) 9+2^2 (3^2÷9-1)÷2^3+100=9+4 (9÷9-1)÷8+100=9+4×0÷8+100=9+0+100=109; d) 10+3^3×25×(2^4÷8-2)^2+5×2^2=10+27×25 (16÷8-2)^2+5×2^2=10+27×25×0^2+5×4=10+0+20=30; e) 3^2+(2^3÷2-2^1÷2^2)÷2=9+(8÷2-2÷4)÷2=9+3,5÷2=9+1,75=10,75; f)( 3^3 )^4÷9-(4^3×2)÷2^1=3^(3×4)÷3^2-[(2^2 )^3×2]÷2^1=3^(12-2)-[2^(6+1)]÷2^1=3^10-2^6=59049-64=58985
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