Răspunsuri

2014-10-14T07:30:07+03:00
Asa, ca inainte de a pleca la facultate:

 \frac{3^1}{3^{log_310}}  - \frac{4^1}{4^{log_45}}-\frac{6^{log_69}}{6^1} = \frac{3}{10^{log_33}} - \frac{4}{5^{log_44}} - \frac{9^{log_66}}{6} = \frac{3}{10} - \frac{4}{5} - \frac{9}{6}

Succes.
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