Ma puteti ajuta va rog frumos cu niste exercitii pe care nu prea le-am inteles a) [(-14/21)^6÷(-2/3)^4-(-18/27)^8÷(-8/12)^6]÷(-8/12)^2 si b) (-5/6)^6÷(-5/6)^4-(-2+1/3)^5÷(2-1/3)^3+(5/6)^2 semnul ^ este putere si / este linie de fractie

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Răspunsuri

Cel mai inteligent răspuns!
2014-10-13T22:45:13+03:00
[(-14/21)^6:(-2/3)^4-(-18/27)^8:(-8/12)^6]:(-8/12)²=
[(-2·7/3·7)^6:(-2/3)^4-(-2·3²/3³)^8:(-2³/3·2²)^6]:(-2³/3·2²)²=simplificam ce se poate
[(-2/3)^6:(-2/3)^4-(-2/3)^8:(-2/3)^6]:(-2/3)²=
[(-2/3)^(6-4)-(-2/3)^(8-6)]:(-2/3)²=
[(-2/3)²-(-2/3)²:4/9=
4/9-4/9·9/4=0·9/4=0

(-5/6)^6:(-5/6)^4-(-2+1/3)^5:(2-1/3)^3+(5/6)²=
(-5/6)^(6-4)-(-2+1/3)^(5-3)+(5/6)²=
(-5/6)²-(-2+1/3)²+(5/6)²=
25/36+25/36-[(-6+1)/3]²=
50/36-(-5/3)²=
50/36-25/9=
50/36-(25·4)/36=
(50-100)/36=-50/36simplif=-25/18=-1,3(8)

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