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Cel mai inteligent răspuns!
2014-10-13T20:54:31+03:00
2t-3=-1/t
2t+1/t-3=0
aducem la acelasi numitor
2t²+1-3t=0
2t²-3t+1=0
Δ=9-8=1
t1=3-1)/4=2/4=1/2
t2=(3+1)/4=1
1 5 1