Răspunsuri

2014-02-23T19:28:41+02:00
Lgx1+lgx2+lgx3+....+lgxn=lg(x1*x2*x3*...*xn) In our case: lg(1/2)+lg(2/3)+...+lg(99/100)= lg((1/2)*(2/3)*(3/4)*...*(98/99)*(99/100))=lg(1/100)=-2

cred....
lg2= (x-1)lgx => lg2= lgx la puterea x-1 => 2=x la puterea x-1 => x=2 :)