Răspunsuri

2014-10-11T21:34:05+03:00
Numerele cerute trebuie sa fie  divizibile cu  6, deci \overline{7ab}=6\cdot k, \ k\in N

700\leq6k\leq799

\dfrac{700}{6}\leq k\leq \dfrac{799}{6}

116,...\leq k\leq133,...

k\in\{117;118;...133\}

\overline{7ab}\in\{6\cdot117;\ 6\cdot118;\ ...\ ;\ 6\cdot133\}
2 4 2