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Cel mai inteligent răspuns!
2014-10-11T16:48:25+03:00
|x|<6 => -6<x<6 => A=(-6, 6)
x>sau=3 => B=[3, +infinit)
AuB = (-6, +infinit)
AnB = [3, 6)
A\B = (-6, 3)
BuN = {3, 4, 5, ..., n}
A\N* = A\{1, 2 ,3 ,4, 5}
2 5 2