Răspunsuri

2014-02-22T18:47:18+02:00
Fe₂O_{x}

(56*2 + 32*x)g oxid ............ 56*2g Fe
28,57g oxid  ....................... 20g Fe

20(112 + 32x) = 112 * 28,57
2240 + 640x = 3200
640x = 960
x = 1,5 => Fe_{2}O_{1,5} => Fe_{4}O_{3}