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  • Utilizator Brainly
2014-02-22T18:31:13+02:00
289=48+x+56+x+50+x
289=154+3x
135=3x
x=45
 I  48+45=93
II  56+45=101
III 50+45=95

2014-02-22T19:58:04+02:00
Metoda figurativa
Fie /-------/ cantitatea care se scoate din fiecare butoi
I    /-------/....48...
II   /-------/......56.......
III  /-------/.......50...         total 289 l
289-(48+56+50)= 135 3 segmente egale
135:3=45 un segment
I=45+48=93 l
II=45+56=101
III=45+50=95l
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