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2014-10-09T20:53:57+03:00
Zn + 2 HCl ---> ZnCl2 + H2
c=md/ms * 100 => md = 150*36/100 = 54 g HCl
65 g Zn............2*36,5 g HCl
x g Zn..............54 g HCl          x = 48,08219 g
puritatea = masa pura/masa impura * 100
masa impura = 41,08219/90 * 100 = 53,425 g Zn
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