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2014-10-09T10:57:32+03:00
 t1=1
t2=t1+1
t3=t2+2
.....
.....
t50=t49+49
Adunand relatiile obtinem:
t1+t2+....t49+t1=t1+t2+....+t49+1+1+2+....+49 ,de unde prin reducere avem: t50=1+49*50/2=1+
1225=1226
1 5 1