Răspunsuri

2014-10-09T09:16:53+03:00
-2≤x-1≤1

-2≤x-1 ⇒  x≥-1  x∈[-1,0.1.2...}
x-1≤1 ⇒ x≤2    x∈{-....-1.0.2]


prin intersectia celor doua rezulta x∈[-1.2]

deci ca numere naturale x=0.1.2

ca numar intreg x=-1.0.1.2.