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2014-10-09T09:51:06+03:00
X+Y=8 si Y+2z=35,

5x+13y+16Z=5x+5y+8y+16z=5(x+y)+8(y+2z)=5*8+8*35=320
  3y+2x+10z=2y+2x+10z+y=2*8+2*35=16+70=86
 7x+10y+6z=7x+7y+3y+6z=7(x+y)+3(y+2z)=7*8+3*35=56+105=161
  4·(2z+y)+3x+3y
=4*35+3*8=140+24=164
63 4 63