Răspunsuri

2014-10-08T21:52:43+03:00
La mijlocul a 2003 termeni se afla termenul al 1001-lea
a 1001=2003
Se spune ca termenii sunt consecutivi si cum a2=a1+1⇒
⇒ a 1001= a1+1000= 2003⇒ a1=2003-1000=1003
dar a 2003=a1+2002=1003+2002=3005
⇒S=1003+1004+......+3005=(1003+3005).*2003/2=4008*2003?2=2003*2004.
a1002=2003
a1002=a1+1001=2003
=2003-1001=1002
***a2003=a1+2002=1002+2002=3004
s=1002+1003+....3004=(1002+3004).2003:2=4006.2003:2=8024018:2=4012009