Răspunsuri

2014-10-06T17:48:00+03:00
(12x1+12x2+12x3+......+12x37):258=12x(1+2+3+37):258=12x43:258=516:258=2
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2014-10-06T17:50:09+03:00
12( 1 + 2 + 3 +....+37) totul supra ( linie de fractie ) 6 ( 1 +2 + 3 +....+37)= (se simplifica cele doua paranteze ) 12 supra 6 = 2 
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