Răspunsuri

2014-10-06T10:14:05+03:00
2 × (1 + 2 + 3 + ... + 2013) ÷ 2014 
1 + 2 + 3 + ... + 2013 -> apicam Suma lui Gauss (n × (n + 1)/2) si avem
2 × 2013(2014 + 1)/2 ÷ 2014 =
= 2013 × 2014 ÷ 2014 = 
= 2013
2014-10-06T10:15:07+03:00
Pai in paranteza ai suma gauss si vei avea:   2[2013x(1+3013)supra 2]:2014=2(2013x2014 supra 2):2014  =2(4054182 supra 2):2014=  2x2027091:2014=2x1006,5=2013