Răspunsuri

2014-10-05T12:05:04+03:00
 (2x-y)^{2} = 4x^{2} -4xy+ y^{2}
 \frac{x}{3} +2  y^{3} +? =  \frac{x}{3} +2 y^{3} +2* \sqrt{2}  y^{ \frac{3}{2} } * \sqrt{ \frac{x}{3} } =  ( \sqrt{ \frac{x}{3} }+ \sqrt{2} y^{ \frac{3}{2} } )  ^{2}
 (3x-2y+ \sqrt{5} )^{2} =9 x^{2} +4 y^{2} +5-12xy+6 \sqrt{5} x-4 \sqrt{5} y
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