Răspunsuri

2014-10-04T22:51:08+03:00

x²-2mx+m(1+m)=0
a=1
b=-2m
c=m(1+m)
Δ= (-2m)²-4m(1+m)
Δ=4m²-4m-4m²
Δ= -4m

a)impunem conditia Δ>0
Δ=-4m>0 |·(-1)
     4m<0⇒m<0⇒m∈(-inf;  0)

b) impunem conditia ca Δ<0
Δ=-4m<0 ⇒ 4m>0⇒m>0⇒m∈(0; +inf)