Răspunsuri

2014-10-04T12:54:12+03:00
Xz+7yz+z=49⇒z(x+7y+1)=49 si x+7y=6⇒x+7y+1=7
din ambele rezulta ca      z·7=49
z=49:7
z=7

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2014-10-04T13:05:55+03:00
X;y;z=? daca:
x+7y=6
xz+7yz+z=49  => z(x+7y+1) = 49 
z(x+7y+1)= z x7 =49 |:7
z=7  


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