Răspunsuri

2014-10-03T10:36:03+03:00
Fie a valoarea ce se scade din fiecare numar. Atunci:
362+a+242+a+258+a=1072
3a+862=1072
3a=1072-862=210
a=210/3=70
Atunci numele sunt:
362+70=432
242+70=312
258+70=328
2014-10-03T13:29:54+03:00
362+a+242+a+258+a=1072
3a+862=1072
3a=1072-862=210
a=210/3=70
nr sunt:
362+70=432
242+70=312
258+70=328