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2014-10-02T19:44:47+03:00

(100a+10b+c) =4(100c+10b+a) + 117  si (a-c) = 5

100a+10b +c = 400c +40b +4a +117 ⇒ 96a - 30b -399c = 117 ⇒                32a-10b-133c=39  ⇒32a - 10b - 133(a-5) = 39      -101a - 10b + 665 = 39 ⇒ 101a +10b = 626   ⇒ 100a +10b +c +5 =626 ⇒ abc = 621 ⇒ a=6, b=2, c=1 621=4×126 +117  (621 =504+117)