Răspunsuri

2014-10-02T14:55:12+03:00
2(3x+1)(1-3x)+(3x-2)²+(3x+2)²
=2[3x(1-3x)+1(1-3x)]+2[(3x-2)²]
=2[3x-9x+1-3x+(3x-2)²]
=6x-18x+2-6x+(3x-2)²
= -12x-6x+2+[(3x)²-2(3x·2)+2²]
= -18x+2+3²x²-2·6x+4
= -18x+2+4+9x²-12x
= -18x-12x+6+9x²
= -30x+9x²+6
mai mult nu stiu :D