Salut imi rezolva si mie cineva un exercitiu va rog...
Radical =r
3(2r2+1)²+2(r2-3)²-(8-r7)(8+r7)

6(r2+3)²+4(3r2-1)²-r288

(r6+2)²+(r3-2r2)²-(r10-r3)(r10+r3)

Multumesc din inima si imi trebuie urgent please

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Răspunsuri

Cel mai inteligent răspuns!
2014-02-19T11:15:59+02:00
3(2sqrt2+1)²+2(sqrt2-3)²-(8-sqrt7)(8+sqrt7) = -8

6(sqrt2+3)²+4(3sqrt2-1)²-sqrt288 = 142

(sqrt6+2)²+(sqrt3-2sqrt2)²-(sqrt10-sqrt3)(sqrt10+sqrt3) = 14

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