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2014-09-30T21:54:28+03:00
CH3-CH2-Cl ----> CH2=CH2 + HCl
64,5 g cloroetan.......1 mol etena
645 g kcloroetan..........x moli etena        x = 10 kmoli
randamentul = nr moli practic/nr moli teoretic * 100
nr moli practic = 80*10/100 = 8 kmoli
pV=nr moli*R*T => V = 8*0,082*400/3=87,466 metri cubi
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