Răspunsuri

2014-09-30T00:17:40+03:00
X+3+y+4+z+5=12 determinati 2014+x+y+z
x+y+z=12-3-4-5;
x+y+z=0+2014=2014
2014-09-30T01:00:21+03:00

x + 3 + y + 4 + z + 5 = 12
x + y+ + z = 12 - 3 - 4 - 5
x + y + z = 0

2014 + x + y + z  = 2014 + 0 = 2014