Răspunsuri

2014-02-18T23:37:00+02:00
Fie  f(x)=aX^{2}+bX+c->un polinom de gradul 2,unde a,b,c∈ R,C etc.
Folosind
\Delta=b^{2}-4ac
Daca \Delta<0 atunci ecuatia ta nu are radacini reale(are 2 radacini complexe)
Daca \Delta=0 atunci x_{1}=x_{2}=\frac{-b}{2a}
Daca \Delta>0 atunci avem relatia:
x_{12}=\frac{-b+-\sqrt{\Delta}}{2a}
De unde :
x_{1}=\frac{-b+\sqrt{\Delta}}{2a}
x_{2}=\frac{-b-\sqrt{\Delta}}{2a}
Sper ca ai inteles.