Daca reactioneaza 10 moli de H20 cu Mg. Sa se afle: a. m Mg care a reactionat....b. numarul de moli de Mg(OH) .......c. Volumul de H2 degajat in conditii normale...........Va rog urgent........

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Răspunsuri

2014-09-26T10:31:35+03:00
2Mg + 2H2O->2 MgOH+H2 nH2O=10 moli. mMg=? nMgOH=? VH2(c.n)=? Rezolvare: a).mMg= n•A;AMg=24moli;nMg=2*10:2=10 moli=> mMg=n•A=240 g. b).nMgOH=2•10:2=10 moli. c). VH2=nH2/22,4. nH2=1•10:2=5 moli. => VH2= 5/22,4
2014-09-26T12:06:57+03:00
Mg + 2 H2O ---> Mg(OH)2 + H2
1 mol Mg.......2 moli H2O.......1 mol Mg(OH)2........22,4 l H2
x moli Mg......10 moli H2O........y moli Mg(OH)2.........z l H2
x = 5 moli Mg
y = 5 moli Mg(OH)2
z = 112 l H2

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