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2014-09-26T12:12:44+03:00
2 Fe + 3 Cl2 ---> 2 FeCl3
2 * 56 g Fe.........3 * 35,5 * 2 g Cl2........2 moli FeCl3
56 g Fe...................x g Cl2.....................y moli FeCl3
x = 106,5 g Cl2
y = 1 mol FeCl3