Răspunsuri

2014-09-25T23:21:01+03:00
3^(n-5)=(3^4)^9:(3^4)^5
3^(n-5)=3^36:3^20
3^(n-5)=3^16⇒ n-5=16⇒ n=21
am folosit formulele
(a^m)^n=a^m*n
a^m : a^n=a^(m-n)
2014-09-25T23:48:23+03:00
3^(n-5)=(3^4)^9:(3^4)^5
3^(n-5)=3^36:3^20
3^(n-5)=3^16⇒ n-5=16⇒ n=21