Răspunsuri

2014-02-17T16:33:46+02:00
Nr impare 1-3-5-7. se vede ca dif e 2

a
a+2
a+2+2

3a+6=405
3a=405-6
3a=399
a=399:3
a=133

urm nr vor fi 
133+2=135
133+2+2=137
2 5 2
2014-02-17T16:36:45+02:00
A+b+c=405
b=a+2
c=a+4
INLOCUIM:
a + (a+2) + (a+4) = 405
facem nr egale scazand diferenta dintre ele
a+a+a=405-(2+4)
3a=405-6
3a=399
a=399:3
a=133
b=a+2
b=133+2
b=135
c=a+4
c=133+4
a=137
1 3 1