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2014-02-17T15:44:38+02:00
2x^2-5x+2=0
delta e b^2-4ac adica 25-16=9
si atunci x1,2= -b+-radical din delta/2 de unde x1=(5+3)/2x2 = 1 si x2=(5-3)/2x2= 1/4
 
2x^2+3x-2=0
delta = 9+16=25
x1=(-3+5)/4 = 2/4 = 1/2
x2= (-3-5)/4 = -2