Răspunsuri

  • Utilizator Brainly
2014-02-17T15:23:58+02:00
Cele 3 numere: x,y,z unde y=x+1, z=y+1=x+2
x+y+z=x+x+1+x+2=3x+3=471 ⇒ 3x=468, x=156, y=157, z=158
2014-02-17T15:27:49+02:00
Numere consecutive
a
a+1
(a+1)+1

suma=471

a+(a+1)+(a+1)+1=471
3a+3=471
3a=471-3
3a=468
a=468:3
a=156

deci nr sunt

156
157
158